
(1) 当两个弹簧串联时,每个弹簧受力都是F,因此:
\[ F = k_1 x_1 = k_2 x_2 \]
由此可以得出:
\[ k_1 x_1 + k_2 x_2 = F \]
解得:
\[ k_1 = \frac{k_1 k_2}{k_1 + k_2} \cdot x_1 \]
\[ k_2 = \frac{k_1 k_2}{k_1 + k_2} \cdot x_2 \]
(2) 两个弹簧并联时,各受力为 \( F/2 \),因此有:
\[ F/2 = k_1 x_1 = k_2 x_2 \]
由于并联,\( x = x_1 = x_2 \),所以:
\[ K = k_1 + k_2 \]