JAVA计算日期,时间差的几种方法

2.采用一个三方的jar包(Joda time library)

3. 利用TimeUnit类(java.util.concurrent 包中)

方法一:手工计算

程序代码

import java.text.SimpleDateFormat;

import java.util.Date;

public class DateDifferentExample {

public static void main(String[] args) {

String dateStart = "01/14/2012 09:29:58";

String dateStop = "01/15/2012 10:31:48";

//HH converts hour in 24 hours format (0-23), day calculation

SimpleDateFormat format = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss");

Date d1 = null;

Date d2 = null;

try {

d1 = format.parse(dateStart);

d2 = format.parse(dateStop);

//in milliseconds

long diff = d2.getTime() - d1.getTime();

long diffSeconds = diff / 1000 % 60;

long diffMinutes = diff / (60 * 1000) % 60;

long diffHours = diff / (60 * 60 * 1000) % 24;

long diffDays = diff / (24 * 60 * 60 * 1000);

System.out.print(diffDays + " days, ");

System.out.print(diffHours + " hours, ");

System.out.print(diffMinutes + " minutes, ");

System.out.print(diffSeconds + " seconds.");

} catch (Exception e) {

e.printStackTrace();

}

}

}

结果为：

程序代码

1 days, 1 hours, 1 minutes, 50 seconds.

方法二：采用 joda-time-2.1.jar (这里去下载:http://joda-time.sourceforge.net/)

程序代码

import java.text.SimpleDateFormat;

import java.util.Date;

import org.joda.time.DateTime;

import org.joda.time.Days;

import org.joda.time.Hours;

import org.joda.time.Minutes;

import org.joda.time.Seconds;

public class JodaDateDifferentExample {

public static void main(String[] args) {

String dateStart = "01/14/2012 09:29:58";

String dateStop = "01/15/2012 10:31:48";

SimpleDateFormat format = new SimpleDateFormat("MM/dd/yyyy HH:mm:ss");

Date d1 = null;

Date d2 = null;

try {

d1 = format.parse(dateStart);

d2 = format.parse(dateStop);

DateTime dt1 = new DateTime(d1);

DateTime dt2 = new DateTime(d2);

System.out.print(Days.daysBetween(dt1, dt2).getDays() + " days, ");

System.out.print(Hours.hoursBetween(dt1, dt2).getHours() % 24 + " hours, ");

System.out.print(Minutes.minutesBetween(dt1, dt2).getMinutes() % 60 + " minutes, ");

System.out.print(Seconds.secondsBetween(dt1, dt2).getSeconds() % 60 + " seconds.");

} catch (Exception e) {

e.printStackTrace();

}

}

}

结果为：

程序代码

1 days, 1 hours, 1 minutes, 50 seconds.

方法三: 采用TimeUnit ( java.util.concurrent包中的TimeUnit)

程序代码

long diffSeconds = diff / 1000 % 60;

long diffMinutes = diff / (60 * 1000) % 60;

程序代码

long diffSeconds = TimeUnit.MILLISECONDS.toSeconds(diff) % 60;

long diffMinutes = Tim

eUnit.MILLISECONDS.toMinutes(diff) % 60;

long diffHours = TimeUnit.MILLISECONDS.toHours(diff) % 24;

long diffDays = TimeUnit.MILLISECONDS.toDays(diff);

文章参考：http://www.yihaomen.com/article/java/361.htm