ACI 440.2R-08 (Errata 2010_07_22)

ERRATA as of July 22nd, 2010

ACI 440.2R-08

Guide for the Design and Construction

of Externally Bonded FRP Systems

for Strengthening Concrete Structures

1st printing

Reported by ACI Committee 440

Section 13.1.2, page 38, paragraph following Eq. (13-1), revised as: In in which κv is calculated using Eq. (11-7)…

Eq. (10-13), page 29, revised as:

M n = A s f s

⎟⎟⎠⎞⎜⎜⎝⎛βΨ+⎟⎟⎠⎞⎜⎜⎝⎛β2211c -h f A c -d e f f f

M n = A s f s ββ⎛⎞⎛⎞−+Ψ−⎜⎟⎜⎟⎝⎠⎝

⎠f f fe f c c d A f d 1122

Eq. (11-8), page 33, revised as: L e =

0.58 in in.-lb units f f f (11-8) L =e

0.58 in SI units f f f

L e =0.58

2500 in in.-lb units ()f f nt E (11-8) L e =0.5823,300

in SI units ()f f nt E

Eq. (12-3), page 35, revised as:

3.3cc

c f a l f f f ′′==ψκ 3.3cc

c f a l f f f ′′=+ψκ

Section 12.2, page 37, last paragraph revised as:

For values of eccentricity greater than 0.1h and up to the point corresponding to the balanced condition, the methodology provided in Appendix A Appendix D may be…

Section 12.4, page 37, last paragraph revised as: The value of k 1 k 2 in Eq. (11-7) can be taken as…

Page 53, design example, Procedure Step 2, revised as:

Cross-sectional area:

A cg = b e h f + b w (h − h f )

A cg = b f h f + b w (h − h f )

Page 53, design example, Step 2 Calculation in inch-pound units revised as: 3

2424 in.2124 in.21(9.3914.5)=51,150 in.×++×− 3

2424 in.2124 in.21(9.39)=51,150 in.12

×++×−10.5

7.75 in.r == 265==0.00528,500

pe ε ==28,500pe

ε1650.00578

Page 54, design example, Step 7 Procedure revised as: 10.035e ps

pe pnet c c P A E ⎛⎞ε=ε+++ε≤⎜⎟⎜⎟⎝⎠22e r 10.035e ps pe pnet c P E ⎛⎞ε=ε+++ε≤⎜⎟⎜⎟⎝⎠

22e r c g A

Page 61, design example, Step 3 Calculation in inch-pound units revised as: 8.18 ksi 6.5 ksi 1.2 ksi l f −== 8.18 ksi 6.5 ksi ksi 3.3 0.425

l f −==×× 1.260.95

Page 61, design example, Step 3 Calculation in SI units revised as:

56.4 MPa 44.8 MPa 8.3 MPa l f −== 56.4 MPa 44.8 MPa MPa 3.3 × 0.425

l f −==×8.70.95

Page 61, design example, Step 4 Procedure revised as:

f f f fe 2l f f fe f n E t =ε

Page 61, design example, Step 4 Calculation in inch-pound units revised as:

0.95233,000ksi 0.013in 8.810in in ××××× .233,000 ksi 0.013 in.×8.8 × 10in.in n ××

Page 61, design example, Step 4 Calculation in SI units revised as: mm 0.95 × 2 × 227,527 MPa × 0.33 mm × 8.8 × 10mm ⎜⎟⎝⎠-3mm 2 × 227,527 MPa × 0.33 mm × 8.8 × 10mm n ⎜⎟⎝

⎠

Last revised on 7-22-10, 10:00 a.m.