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3~10kV电动机-电流速断保护整定计算

来源:动视网 责编:小OO 时间:2025-10-03 19:59:30
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3~10kV电动机-电流速断保护整定计算

3~10kV电动机-电流速断保护整定计算一、计算条件可靠系数:Krel=1.32接线系数:Kjx=1电动机起动电流倍数:Kst=7电流互感器变比:nTA=15电动机额定电流:IrM=35.9(A)最小运行方式下,电动机接线端两相短路时,流过保护安装处的超瞬态电流:I"k2·min=7000(A)二、计算公式及结果保护装置的动作电流:异步电动机(应躲过电动机的起动电流):Iop·K=Krel*Kjx*Kst*IrM/nTA=1.32*1*7*35.9/15=22.1144(A)保护装置的灵敏系数
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导读3~10kV电动机-电流速断保护整定计算一、计算条件可靠系数:Krel=1.32接线系数:Kjx=1电动机起动电流倍数:Kst=7电流互感器变比:nTA=15电动机额定电流:IrM=35.9(A)最小运行方式下,电动机接线端两相短路时,流过保护安装处的超瞬态电流:I"k2·min=7000(A)二、计算公式及结果保护装置的动作电流:异步电动机(应躲过电动机的起动电流):Iop·K=Krel*Kjx*Kst*IrM/nTA=1.32*1*7*35.9/15=22.1144(A)保护装置的灵敏系数
                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                  3~10kV电动机-电流速断保护整定计算

一、计算条件

    可靠系数:Krel=1.32

    接线系数:Kjx=1

    电动机起动电流倍数:Kst=7

    电流互感器变比:nTA=15

    电动机额定电流:IrM=35.9(A)

    最小运行方式下,电动机接线端两相短路时,流过保护安装处的超瞬态电流:I"k2·min=7000(A)

二、计算公式及结果

    保护装置的动作电流:

    异步电动机(应躲过电动机的起动电流):

    Iop·K=Krel*Kjx*Kst*IrM/nTA

          =1.32*1*7*35.9/15

          =22.1144(A)

    保护装置的灵敏系数(按最小运行方式下,电动机接线端两相短路时,流过保护安装处的短路电流校验):

    Ksen=I"k2·min/Iop=I"k2·min*Kjx/(Iop·K*nTA)

        =7000*1/(22.11*15)

        =21.1≥2

    保护装置的灵敏系数大于等于2,符合要求!

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3~10kV电动机-电流速断保护整定计算

3~10kV电动机-电流速断保护整定计算一、计算条件可靠系数:Krel=1.32接线系数:Kjx=1电动机起动电流倍数:Kst=7电流互感器变比:nTA=15电动机额定电流:IrM=35.9(A)最小运行方式下,电动机接线端两相短路时,流过保护安装处的超瞬态电流:I"k2·min=7000(A)二、计算公式及结果保护装置的动作电流:异步电动机(应躲过电动机的起动电流):Iop·K=Krel*Kjx*Kst*IrM/nTA=1.32*1*7*35.9/15=22.1144(A)保护装置的灵敏系数
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