按天去除重复数据,为0则取0,否则取最大的那个值_MySQL

测试数据：mysql> select * from t2;+----+--------+---------------------+------------+| id | userid | inputDate | infoStatus |+----+--------+---------------------+------------+| 1 | 1 | 2014-07-11 00:00:00 | 20013 | | 2 | 1 | 2014-07-11 00:00:00 | 0 | | 3 | 2 | 2014-07-12 00:00:11 | 20015 | | 4 | 2 | 2014-07-12 00:00:22 | 20013 | | 5 | 2 | 2014-07-14 00:00:00 | 0 | | 6 | 2 | 2014-07-15 00:00:00 | 20013 | | 7 | 2 | 2014-07-15 00:00:00 | 0 | | 8 | 2 | 2014-07-16 00:00:00 | 0 | | 9 | 2 | 2014-07-13 00:00:00 | 20013 | | 10 | 2 | 2014-07-13 00:00:00 | 0 | | 11 | 2 | 2014-07-14 00:00:00 | 0 | +----+--------+---------------------+------------+查询sql：select id,userid,date(inputDate) as date,max(infoStatus) as m,min(infoStatus) as i,if(min(infoStatus)=0,0,max(infoStatus)) as max from t2 where infoStatus = 0 or infoStatus <= 99999 group by date;回执结果：+----+--------+------------+-------+-------+-------+| id | userid | date | m | i | max |+----+--------+------------+-------+-------+-------+| 1 | 1 | 2014-07-11 | 20013 | 0 | 0 | | 3 | 2 | 2014-07-12 | 20015 | 20013 | 20015 | | 9 | 2 | 2014-07-13 | 20013 | 0 | 0 | | 5 | 2 | 2014-07-14 | 0 | 0 | 0 | | 6 | 2 | 2014-07-15 | 20013 | 0 | 0 | | 8 | 2 | 2014-07-16 | 0 | 0 | 0 | +----+--------+------------+-------+-------+-------+我的思路是按照时间分组，并同时查询最小，跟最大的，如果最小的为0，那max字段就为0，否则就取最大的那个