MySQL中文汉字转拼音的自定义函数和使用实例(首字的首字母)

fristPinyin ： 此函数是将一个中文字符串的第一个汉字转成拼音字母 （例如："中国人"->Z）
代码如下:
CREATE FUNCTION `fristPinyin`(P_NAME VARCHAR(255)) RETURNS varchar(255) CHARSET utf8
BEGIN
    DECLARE V_RETURN VARCHAR(255);
    SET V_RETURN = ELT(INTERVAL(CONV(HEX(left(CONVERT(P_NAME USING gbk),1)),16,10),
        0xB0A1,0xB0C5,0xB2C1,0xB4EE,0xB6EA,0xB7A2,0xB8C1,0xB9FE,0xBBF7,
        0xBFA6,0xC0AC,0xC2E8,0xC4C3,0xC5B6,0xC5BE,0xC6DA,0xC8BB,
        0xC8F6,0xCBFA,0xCDDA,0xCEF4,0xD1B9,0xD4D1),   
    'A','B','C','D','E','F','G','H','J','K','L','M','N','O','P','Q','R','S','T','W','X','Y','Z');
    RETURN V_RETURN;
END
pinyin ：此函数是将一个中文字符串对应拼音母的每个相连 (例如："中国人"->ZGR)
代码如下:
CREATE FUNCTION `pinyin`(P_NAME VARCHAR(255)) RETURNS varchar(255) CHARSET utf8
BEGIN
    DECLARE V_COMPARE VARCHAR(255);
    DECLARE V_RETURN VARCHAR(255);
    DECLARE I INT;

    SET I = 1;
    SET V_RETURN = '';
    while I < LENGTH(P_NAME) do
        SET V_COMPARE = SUBSTR(P_NAME, I, 1);
        IF (V_COMPARE != '') THEN
            #SET V_RETURN = CONCAT(V_RETURN, ',', V_COMPARE);
            SET V_RETURN = CONCAT(V_RETURN, fristPinyin(V_COMPARE));
            #SET V_RETURN = fristPinyin(V_COMPARE);
        END IF;
        SET I = I + 1;
    end while;

    IF (ISNULL(V_RETURN) or V_RETURN = '') THEN
        SET V_RETURN = P_NAME;
    END IF;

    RETURN V_RETURN;
END
示例：
代码如下:
mysql> select p.province, fristPinyin(p.province), pinyin(p.province) from province p;
+------------------+-------------------------+--------------------+
| province         | fristPinyin(p.province) | pinyin(p.province) |
+------------------+-------------------------+--------------------+
| 北京市           | B                       | BJS                |
| 天津市           | T                       | TJS                |
| 河北省           | H                       | HBS                |
| 山西省           | S                       | SXS                |
| 内蒙古自治区     | N                       | NMGZZQ             |
+------------------+-------------------------+--------------------+
5 rows in set

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