mysql-求一个Mysql语句查询出当前周的数据按照天分组
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时间:2020-11-09 16:49:02
mysql-求一个Mysql语句查询出当前周的数据按照天分组
mysql-求一个Mysql语句查询出当前周的数据按照天分组:mysql数据数据库 SELECT DATE_FORMAT(uploadTime_beg, %Y-%m-%d) as time, SUM(field01) as sumStatus1, SUM(field02) as sumStatus2, SUM(field03) as sumStatus3, SUM(field04) as sumStatu
导读mysql-求一个Mysql语句查询出当前周的数据按照天分组:mysql数据数据库 SELECT DATE_FORMAT(uploadTime_beg, %Y-%m-%d) as time, SUM(field01) as sumStatus1, SUM(field02) as sumStatus2, SUM(field03) as sumStatus3, SUM(field04) as sumStatu

mysql数据数据库
SELECT
DATE_FORMAT(uploadTime_beg, "%Y-%m-%d") as time,
SUM(field01) as sumStatus1,
SUM(field02) as sumStatus2,
SUM(field03) as sumStatus3,
SUM(field04) as sumStatus4,
SUM(field05) as sumStatus5
FROM
health_realdata
WHERE DATE_FORMAT(uploadTime_beg,'%Y%u') = DATE_FORMAT(CURDATE(),'%Y%u')
GROUP BY DATE_FORMAT(uploadTime_beg,"%Y-%m-%d");
这个SQL查出的数据如下:  我想要的效果是:虽然数据库中没有2015-11-25的数据,但是也要查出来,只是后面的值显示为0. 请问在MYSQL中如何实现,上面的SQL如何修改呢。 我看到网上说需要一个日历辅助表,说的不是很详细,我试了一下好像有问题,如果这种方法可行,还请大牛们写详细点,谢谢。
mysql-求一个Mysql语句查询出当前周的数据按照天分组
mysql-求一个Mysql语句查询出当前周的数据按照天分组:mysql数据数据库 SELECT DATE_FORMAT(uploadTime_beg, %Y-%m-%d) as time, SUM(field01) as sumStatus1, SUM(field02) as sumStatus2, SUM(field03) as sumStatus3, SUM(field04) as sumStatu