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CodeforcesRound#219(Div.2)B.MakingSequencesisFun

来源:动视网 责编:小采 时间:2020-11-09 07:19:36
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CodeforcesRound#219(Div.2)B.MakingSequencesisFun

CodeforcesRound#219(Div.2)B.MakingSequencesisFun:We'll define S ( n ) for positive integer n as follows: the number of the n 's digits in the decimal base. For example, S (893)=3 , S (114514)=6 . You want to make a consecutive integer sequence starting from number m ( m , m 。1。..
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导读CodeforcesRound#219(Div.2)B.MakingSequencesisFun:We'll define S ( n ) for positive integer n as follows: the number of the n 's digits in the decimal base. For example, S (893)=3 , S (114514)=6 . You want to make a consecutive integer sequence starting from number m ( m , m 。1。..


We'll define S ( n ) for positive integer n as follows: the number of the n 's digits in the decimal base. For example, S (893)?=?3 , S (114514)?=?6 . You want to make a consecutive integer sequence starting from number m ( m ,? m ??1,?...

We'll define S(n) for positive integer n as follows: the number of the n's digits in the decimal base. For example,S(893)?=?3, S(114514)?=?6.

You want to make a consecutive integer sequence starting from number m (m,?m?+?1,?...). But you need to payS(nk to add the number n to the sequence.

You can spend a cost up to w, and you want to make the sequence as long as possible. Write a program that tells sequence's maximum length.

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CodeforcesRound#219(Div.2)B.MakingSequencesisFun

CodeforcesRound#219(Div.2)B.MakingSequencesisFun:We'll define S ( n ) for positive integer n as follows: the number of the n 's digits in the decimal base. For example, S (893)=3 , S (114514)=6 . You want to make a consecutive integer sequence starting from number m ( m , m 。1。..
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标签: ma round Codeforces
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