python二叉树遍历的实现方法

来源：动视网责编：小采时间：2020-11-27 14:29:49

python二叉树遍历的实现方法

python二叉树遍历的实现方法: 代码如下:#!/usr/bin/python# -*- coding: utf-8 -*- class TreeNode(object): def __init__(self,data=0,left=0,right=0): self.data = data self.left = left self.right = right class BTree(

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导读python二叉树遍历的实现方法: 代码如下:#!/usr/bin/python# -*- coding: utf-8 -*- class TreeNode(object): def __init__(self,data=0,left=0,right=0): self.data = data self.left = left self.right = right class BTree(

代码如下:

#!/usr/bin/python
# -*- coding: utf-8 -*-

class TreeNode(object):
def __init__(self,data=0,left=0,right=0):
self.data = data
self.left = left
self.right = right

class BTree(object):
def __init__(self,root=0):
self.root = root

def is_empty(self):
if self.root is 0:
return True
else:
return False

def preOrder(self,treenode):
if treenode is 0:
return
print treenode.data
self.preOrder(treenode.left)
self.preOrder(treenode.right)

def inOrder(self,treenode):
if treenode is 0:
return
self.inOrder(treenode.left)
print treenode.data
self.inOrder(treenode.right)

def postOrder(self,treenode):
if treenode is 0:
return
self.postOrder(treenode.left)
self.postOrder(treenode.right)
print treenode.data

n1 = TreeNode(data=1)
n2 = TreeNode(2,n1,0)
n3 = TreeNode(3)
n4 = TreeNode(4)
n5 = TreeNode(5,n3,n4)
n6 = TreeNode(6,n2,n5)
n7 = TreeNode(7,n6,0)
n8 = TreeNode(8)
root = TreeNode('root',n7,n8)

bt = BTree(root)
print 'preOrder......'
print bt.preOrder(bt.root)
print 'inOrder......'
print bt.inOrder(bt.root)
print 'postOrder.....'
print bt.postOrder(bt.root)

结果：

preOrder......
root
7
6
2
1
5
3
4
8

inOrder......
1
2
6
3
5
4
7
root
8

postOrder.....
1
2
3
4
5
6
7
8
root