python比较2个xml内容的方法

from xml.etree import ElementTree 
OK=True 
main_pid = 10000 
loop_depth = 0 
def compare_xml(left, right, key_info='.'):
 global loop_depth 
 loop_depth += 1 
 if loop_depth == 1: print 
 if left.tag != right.tag: 
 print_diff(main_pid, key_info, 'difftag', left.tag, right.tag)
 return 
 if left.text != right.text: 
 print_diff(main_pid, key_info, 'difftext', left.text, right.text)
 return 
 leftitems = dict(left.items()) 
 rightitems = dict(right.items()) 
 for k,v in leftitems.items(): 
 if k not in rightitems: 
 s = '%s/%s' % (key_info, left.tag) 
 print_diff(main_pid, s, 'lostattr', k, "")
 for k,v in rightitems.items(): 
 if k not in leftitems: 
 s = '%s/%s' % (key_info, right.tag) 
 print_diff(main_pid, s, 'extraattr', "", k)
 leftnodes = left.getchildren() 
 rightnodes = right.getchildren() 
 leftlen = len(leftnodes) 
 rightlen = len(rightnodes) 
 if leftlen != rightlen: 
 s = '%s/%s' % (key_info, right.tag)
 print_diff(main_pid, s, 'difflen', leftlen, rightlen)
 return 
 l = leftlen %-40s [ %s != %s ]'%(msg.upper(), main_pid, key_info.strip('./'), base_type, test_type)
 print info.encode('gbk')
 OK = False

if __name__ == '__main__': 
 s1 = '''''<?xml version="1.0" encoding="UTF-8"?> 
  
  
 linux 
 30 
  
  
 windows 
 20 
  
 ''' 
 s2 = '''''<?xml version="1.0" encoding="UTF-8"?> 
  
  
 windows 
 20 
  
  
 linux 
 30 
  
 ''' 
 lroot = ElementTree.fromstring(s1) 
 rroot = ElementTree.fromstring(s2) 
 compare_xml(lroot, rroot)