CodeforcesRound#277.5(Div.2)-C_html/css

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CodeforcesRound#277.5(Div.2)-C_html/css

CodeforcesRound#277.5(Div.2)-C_html/css_WEB-ITnose:简单细节题： #include#include#include#include#include#include#define rep(i,a,b) for(int i=(a);i=(b);i--)#define clr(a,x) memset(a,x,sizeof a)typedef long long LL;using namespace std;

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导读CodeforcesRound#277.5(Div.2)-C_html/css_WEB-ITnose:简单细节题： #include#include#include#include#include#include#define rep(i,a,b) for(int i=(a);i=(b);i--)#define clr(a,x) memset(a,x,sizeof a)typedef long long LL;using namespace std;

简单细节题：

#include#include#include#include#include#include#define rep(i,a,b) for(int i=(a);i<(b);i++)#define rev(i,a,b) for(int i=(a);i>=(b);i--)#define clr(a,x) memset(a,x,sizeof a)typedef long long LL;using namespace std;const int mod=1e9 +7;const int maxn=105;const int maxm=905;int da[maxn],db[maxn];int main(){ int n,m; while(~scanf("%d%d",&n,&m)) { if(m>9*n||(n!=1&&m==0)) { printf("-1 -1\n"); continue; } int cnt=0,ccnt=0,num=m; while(num-9>=0)db[ccnt++]=9,num-=9; if(num)db[ccnt++]=num; while(n!=ccnt)db[ccnt++]=0; num=m; while(1<=num-9)da[cnt++]=9,num-=9; if(n-1==cnt) { da[cnt++]=num; for(int i=cnt-1;i>=0;i--) printf("%d",da[i]); printf(" "); for(int i=0;i=0;i--) printf("%d",da[i]); printf(" "); for(int i=0;i

C. Given Length and Sum of Digits...

time limit per test

1 second

memory limit per test

256 megabytes

input

standard input

output

standard output

You have a positive integer m and a non-negative integer s. Your task is to find the smallest and the largest of the numbers that have length m and sum of digits s. The required numbers should be non-negative integers written in the decimal base without leading zeroes.

Input

The single line of the input contains a pair of integers m, s (1?≤?m?≤?100,?0?≤?s?≤?900) ? the length and the sum of the digits of the required numbers.

Output

In the output print the pair of the required non-negative integer numbers ? first the minimum possible number, then ? the maximum possible number. If no numbers satisfying conditions required exist, print the pair of numbers "-1 -1" (without the quotes).

Sample test(s)

input