任意位置显示html菜单_典型特效

把如下代码加入区域中

document.onclick = popUp

function popUp() {

newX = window.event.x + document.body.scrollLeft

newY = window.event.y + document.body.scrollTop

menu = document.all.itemopen

if ( menu.style.display == ""){

menu.style.display = "none" }

else {

menu.style.display = ""}

menu.style.pixelLeft = newX - 50

menu.style.pixelTop = newY - 50

}

//-->