Ajax提交表单页面后阻止刷新的方法

<form>
 <p class="col-md-9 col-sm-9 col-xs-12 col-md-offset-3">
 <input type="button" class="btn btn-info" value="重置" onclick="return resetaa()">
 <input type="button" class="btn btn-success" value="提交" onclick="return formCheck()">
</form>
 <script type="text/JavaScript">
 function formCheck(){
 $.ajax({
 type: "post",
 url:'/fudaMes/orderInfo/insertOrderInfo',
 data:$('#formId').serialize(),// 你的formid
 async: true,
 error: function(request) {
 new PNotify({
 title: '提交失败',
 text: '信息录入失败',
 type: 'error',
 styling: 'bootstrap3'
 });
 },
 success: function(data) {
 if(data=="success"){
 new PNotify({
 title: '提交成功',
 text: '订单信息已录入',
 type: 'success',
 styling: 'bootstrap3'
 }); 
 }else{
 new PNotify({
 title: '提交失败',
 text: '信息录入失败',
 type: 'error',
 styling: 'bootstrap3'
 });
 } 
 }
 });
 }
</script>