layui结合form,table的全选、反选v1.0示例讲解

<div class="layui-form">
<table class="layui-table">
 <thead>
 <tr>
 <td>
 <input type="checkbox" name="" lay-skin="primary" lay-filter="allChoose">
 </td>
 <td>ID</td>
 <td>角色名</td>
 <td>唯一标识</td>
 <td>状态</td>
 <td>操作</td>
 </tr>
 </thead>
 <tbody class="role_list">
 <tr>
 <td>
 <input type="checkbox" name="" lay-skin="primary" lay-filter="itemChoose">
 </td>
 <td>1</td>
 <td>xxx</td>
 <td>xxx</td>
 <td>xxx</td>
 <td>xxx</td>
 </tr>
 </tbody>
</table>
</div>

form.on('checkbox(allChoose)', function(data){
 var child = $(data.elem).parents('table').find('tbody input[type="checkbox"]');
 child.each(function(index, item){
 item.checked = data.elem.checked;
 });
 form.render('checkbox');
});
form.on('checkbox(itemChoose)',function(data){
 var sib = $(data.elem).parents('table').find('tbody input[type="checkbox"]:checked').length;
 var total = $(data.elem).parents('table').find('tbody input[type="checkbox"]').length;
 if(sib == total){
 $(data.elem).parents('table').find('thead input[type="checkbox"]').prop("checked",true);
 form.render();
 }else{
 $(data.elem).parents('table').find('thead input[type="checkbox"]').prop("checked",false);
 form.render();
 }
});